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JEE MATHEMATICS MCQ: PAIR OF STRAIGHT LINES

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Application +4 | -1
The equation of the bisector of the acute angle between the lines 3x−4y+7=03x - 4y + 7 = 0 and 12x+5y−2=012x + 5y - 2 = 0 is
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Correct option: C
21x+77y−101=021x + 77y - 101 = 0
Option C (21x+77y−101=021x + 77y - 101 = 0) is correct because it is the equation of the bisector of the acute angle between the two lines, determined by checking the sign of a1a2+b1b2a_1a_2 + b_1b_2.

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