The argument of the complex number $\frac{{13 - 5i}}{{4 - 9i}}$ is

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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The argument of the complex number

\frac{{13 - 5i}}{{4 - 9i}}

View answer and explanation

Correct option: B

\frac{\pi }{4}

Option B

\frac{\pi }{4}

is correct because it is the argument of the simplified complex number, found by rationalizing the denominator and calculating the arctangent of the imaginary to real part ratio.

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The number of non-zero integer solutions of the equation

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is If

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z, \frac{z}{1-z^2}

Let

\left|z_r-r\right| \leq r, \forall r=1,2,3, \ldots, n

, then

\left|\sum\limits_{r=1}^n z_r\right|

is less than The roots of the cubic equation

(z+a b)^3=a^3

, where

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. Number of solutions of the equation

{z^2} + {\left| z \right|^2} = 0,

where

z \in C

is If

2x = - 1 + \sqrt 3 i

, then the value of

{\left( {1 - {x^2} + x} \right)^6} - {\left( {1 - x + {x^2}} \right)^6}

is equal to