Skip to main content
Back to PROPERTIES OF TRIANGLES

JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy
1 of 1
Analyzing +4 | -1
If the area of a Δ  ABC\Delta \;ABC is given by Δ=a2−(b−c)2\Delta = {a^2} - {\left( {b - c} \right)^2}, then tan⁡(A2)\tan \left( {\frac{A}{2}} \right) is equal to
View answer and explanation
Correct option: C
14\frac{1}{4}
Option C (14\frac{1}{4}) is correct because by simplifying the given area equation and using Heron's formula, we can find that tan⁡A2=14\tan \frac{A}{2} = \frac{1}{4}.

More Questions from PROPERTIES OF TRIANGLES

Practice All Chapter MCQs →
If p1,p2,p3{p_1},{p_2},{p_3} are altitudes of a Δ  ABC\Delta \;ABC drawn from the vertices A,B,CA,B,C and Δ\Delta the area of the triangle, then p1−2+p2−2+p3−2p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2} is equal to If the sides of the triangles are 5k,  6k,  5k5k,\;6k,\;5k and radius of incircle is 6, the value of kk is equal to In a Δ ABC\Delta \,ABC, if a=(b−c)sec⁡θa = \left( {b - c} \right)\sec \theta, then 2 bcb−c  sin⁡  A2=\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} = In Δ  ABC,b+ca\Delta \;ABC,\frac{{b + c}}{a} is equal to If Δ=a2−(b−c)2\Delta = {a^2} - {\left( {b - c} \right)^2}, where Δ\Delta is the area of Δ  ABC\Delta \;ABC, then tan⁡A\tan A is equal to If AA is the area and 2s2 s is the sum of the sides of a triangle, then
Type at least 2 characters or jump directly:
🩺 NEET MCQs 🔬 JEE MCQs 🎯 JEE College Predictor Study guides 📊 Dashboard
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.

Continue with Free Account →