JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Medium

1 of 1

Application +4 | -1

If the sum of the squares of the intercepts on the axes cut off by the tangent to the curve

{x^{1/3}} + {y^{1/3}} = {a^{1/3}}

(with

a > 0

) at

P\left( {a/8,\;a/8} \right)

is 2, then

a =

View answer and explanation

Correct option: C

Option C (

\frac{x}{b}

) is correct because it represents the acceleration of the particle, derived by differentiating the given equation with respect to time.

More Questions from TANGENTS & NORMALS

Practice All Chapter MCQs →

a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z