Skip to main content
Back to TANGENTS & NORMALS

JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy
1 of 1
Application +4 | -1
If the function f(x)=x2+α/xf(x)=x^2+\alpha / x has a local minimum at x=2x=2, then the value of α\alpha is
View answer and explanation
Correct option: C
16
Option C (16) is correct because the value of alpha is 16, which is found by setting the first derivative of the function equal to zero at x=2 and solving for alpha.

More Questions from TANGENTS & NORMALS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.