JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy

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Application +4 | -1

The solution of the differential equation

\frac{d^2 y}{d x^2}=x+e^{3 x}

when

y_1(0)=\frac{1}{3}

and

y(0)=0

View answer and explanation

Correct option: B

y=\frac{1}{18}\left(3 x^3+2 e^{3 x}-2\right)

Option B (

y=\frac{1}{18}(3 x^3+2 e^{3 x}-2)

) is correct because it satisfies the given differential equation and the initial conditions

y_1(0)=\frac{1}{3}

and

y(0)=0

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