${\rm{C}}{{\rm{u}}^ + }\left( {aq} \right)$ is unstable in solution and undergoes simultaneous oxidation and reduction, according to the reaction $2{\rm{C}}{{\rm{u}}^ + }\left( {aq} \right)\leftrightharpoons{\rm{C}}{{\rm{u}}^{2 + }}\left( {aq} \right) + {\rm{Cu}}\left( s \right)$ choose correct ${E^ \circ }$ for the above reaction if $E_{{\rm{C}}{{\rm{u}}^{2 + }}/{\rm{Cu}}}^ \circ = 0.34{\rm{V}},E_{{\rm{C}}{{\rm{u}}^{2 + }}/{\rm{C}}{{\rm{u}}^ + }}^ \circ = 0.15{\rm{V}}$

NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

1 Hard

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Application +4 | -1

\mathrm{C}{\mathrm{u}^ + }\left( {aq} \right)

is unstable in solution and undergoes simultaneous oxidation and reduction, according to the reaction

2\mathrm{C}{\mathrm{u}^ + }\left( {aq} \right)\leftrightharpoons\mathrm{C}{\mathrm{u}^{2 + }}\left( {aq} \right) + \mathrm{Cu}\left( s \right)

choose correct

{E^ \circ }

for the above reaction if

E_{\mathrm{C}{\mathrm{u}^{2 + }}/\mathrm{Cu}}^ \circ = 0.34\mathrm{V},E_{\mathrm{C}{\mathrm{u}^{2 + }}/\mathrm{C}{\mathrm{u}^ + }}^ \circ = 0.15\mathrm{V}

View answer and explanation

Correct option: C

+0.38 V

Option C (+0.38 V) is correct because it is calculated by combining the standard reduction potentials of the given half-reactions.