JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

f(x)

is defined on

\left[ {0,\;1} \right],

then the domain of

f\left( {3{x^2}} \right),

View answer and explanation

Correct option: B

\left[ { - 1/\sqrt 3 ,1/\sqrt 3 } \right]

Option B is correct because the domain of f(3x²) is found by ensuring 0 <= 3x² <= 1, which leads to the interval [-1/sqrt(3), 1/sqrt(3)].

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