In a current I given by ${I_{\rm{o}}}\sin \left[ {\omega t - \frac{\pi }{2}} \right]$ flows in an AC circuit across which an AC potential of $E = {E_{\rm{o}}}$ sin wt has been applied, then the power consumption $P$ in the circuit will be

$P = \frac{{{E_{\rm{o}}}{I_{\rm{o}}}}}{{\sqrt 2 }}$

$P = \sqrt 2 {E_{\rm{o}}}{I_{\rm{o}}}$

$P = \frac{{{E_{\rm{o}}}{I_{\rm{o}}}}}{2}$

NEET UG PHYSICS MCQ: ALTERNATING CURRENT

1 Medium

1 of 1

Application +4 | -1

In a current I given by

{I_\mathrm{o}}\sin \left[ {\omega t - \frac{\pi }{2}} \right]

flows in an AC circuit across which an AC potential of

E = {E_\mathrm{o}}

sin wt has been applied, then the power consumption

P

in the circuit will be

View answer and explanation

Correct option: D

P = 0

Option D (P = 0) is correct because the phase difference between the voltage and current is π/2, resulting in zero average power consumption.