5 moles of ${\rm{S}}{{\rm{O}}_2}\;$ and 5 moles of ${{\rm{O}}_2}\;$ are allowed to react to forms ${\rm{S}}{{\rm{O}}_3}$ in a closed vessel. At the equilibrium stage 60% of ${\rm{S}}{{\rm{O}}_2}\;$ is used up. The total number of moles of $\;{\rm{S}}{{\rm{O}}_2}\;,{{\rm{O}}_2}\;and\;{\rm{S}}{{\rm{O}}_3}$ in the vessel now is

NEET UG CHEMISTRY MCQ: Equilibrium

1 Medium

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Application +4 | -1

5 moles of

\mathrm{S}{\mathrm{O}_2}\;

and 5 moles of

{\mathrm{O}_2}\;

are allowed to react to forms

\mathrm{S}{\mathrm{O}_3}

in a closed vessel. At the equilibrium stage 60% of

\mathrm{S}{\mathrm{O}_2}\;

is used up. The total number of moles of

\;\mathrm{S}{\mathrm{O}_2}\;,{\mathrm{O}_2}\;and\;\mathrm{S}{\mathrm{O}_3}

in the vessel now is

View answer and explanation

Correct option: A

8.5

Option A (

6.08 \times {10^{ - 6}}

) is correct because the overall formation constant is the product of the individual stepwise formation constants.

Practice All Chapter MCQs →

Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}