JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

1 Medium

1 of 1

Application +4 | -1

A large number of droplets, each of radius

a

, coalesce to form a bigger drop of radius

b

. Assume that the energy released in the process is converted into the kinetic energy of the drop. The velocity of the drop is

(S=

surface tension and

\rho=

density of drop)

View answer and explanation

Correct option: B

\left[\frac{6 S}{\rho}\left(\frac{1}{a}-\frac{1}{b}\right)\right]^{1 / 2}

Option B (

\left[\frac{{6 S}}{{\rho}}\left(\frac{{1}}{{a}} - \frac{{1}}{{b}}\right)\right]^{1 / 2}

) is correct because it represents the velocity derived from equating the energy released during coalescence to the kinetic energy of the resulting drop.

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