If $f(x)=\frac{x^2-2 x+4}{x^2+2 x+4}, x \in R$ then range of function is :

$\left(-\infty, \frac{1}{3}\right)$

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

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Application +4 | -1

f(x)=\frac{x^2-2 x+4}{x^2+2 x+4}, x \in R

then range of function is :

View answer and explanation

Correct option: D

\left[\frac{1}{3}, 3\right]

Option D (

\left[\frac{1}{3}, 3\right]

) is correct because it represents the range of the function, found by analyzing the quadratic equation and its discriminant.

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