JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy

1 of 1

Application +4 | -1

\frac{{dy}}{{dx}} + \frac{3}{{{{\cos }^2}x}}y = \frac{1}{{{{\cos }^2}x}},x \in \left( {\frac{{ - \pi }}{3},\frac{\pi }{3}} \right)

and

y\left( {\frac{\pi }{4}} \right) = \frac{4}{3},

then

y\left( { - \frac{\pi }{4}} \right)

equals

View answer and explanation

Correct option: A

\frac{1}{3} + {e^6}

Option C ((-1/2, 4, 0)) is correct because it satisfies the given conditions: b = 2a and a is perpendicular to c.

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