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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1
If sin⁡  θ+cos⁡  θ=2cos⁡  θ\sin \,\,\theta + \cos \,\,\theta = \sqrt 2 \cos \,\,\theta then cos⁡  θ−sin⁡  θ\cos \,\,\theta - \sin \,\,\theta is equal to
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Correct option: B
2  sin⁡θ\sqrt 2 \,\,\sin \theta
Option B (2 sin⁡θ\sqrt 2 \,\sin \theta) is correct because it is derived by squaring the given equation and using trigonometric identities to find the value of cos⁡θ−sin⁡θ\cos \theta - \sin \theta.

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