Skip to main content
Back to ATOMS

NEET UG PHYSICS MCQ: ATOMS

1 Medium
1 of 1
Application +4 | -1
If wavelength corresponding to 2nd line of Lyman series is λ\lambda, then the wavelength corresponding to last line of Balmer series will be
View answer and explanation
Correct option: B
32λ9\frac{{32\lambda }}{9}
Option B (32λ9\frac{{32\lambda }}{9}) is correct because the wavelength of the 2nd line of the Lyman series is related to the Rydberg constant, and the wavelength of the last line of the Balmer series is also related to the Rydberg constant. By setting up the equations and solving for the last line of the Balmer series in terms of λ\lambda, the correct answer is obtained.

More Questions from ATOMS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.