Skip to main content
Back to ATOMS

NEET UG PHYSICS MCQ: ATOMS

1 Medium
1 of 1
Application +4 | -1
In a spectrum of hydrogen atom, the ratio of shortest wavelength in Lyman series to longest wavelength in Paschen series is
View answer and explanation
Correct option: D
7144\frac{7}{{144}}
Option D (7144\frac{7}{{144}}) is correct because the shortest wavelength in the Lyman series corresponds to the transition from n=∞\infty to n=1, and the longest wavelength in the Paschen series corresponds to the transition from n=4 to n=3. Using the Rydberg formula, the ratio can be calculated.

More Questions from ATOMS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.