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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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A hydraulic lift is designed such that cross sectional area of its arms are

5 \mathrm{~cm}^2 \, \& \, 10 \mathrm{~m}^2

. Find the force applied by mechanic on smaller area in order to lift a car of

5000 \mathrm{~kg}?

View answer and explanation

Correct option: B

2.5 \mathrm{~N}

The correct answer is B (2.5 N) because it is found by applying Pascal's principle to the hydraulic lift, relating the forces and areas.

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The average mass that must be lifted by a hydraulic press is

80 \mathrm{~kg}

. If the radius of the larger piston is five times that of the smaller piston, what is the minimum force that must be applied? A small drop of oil spreads over water because A film of water is formed between two straight parallel wires of length

20 \mathrm{~cm}

with separation of

0.5 \mathrm{~cm}

. The work done to increase the separation by

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is: The velocity of water in a river is

15 \mathrm{~m} / \mathrm{s}

near the surface. If the river is

5 \mathrm{~m}

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=10^{-2}

poise. A liquid rises to a height of 2 cm in a capillary tube. The angle of contact between the solid and the liquid is zero. The tube is depressed more so that the top of capillary tube is only one cm above the liquid. Then the apparent angle of contact between the solid and liquid is An object weights

m_1

in a liquid of density

d_1

and that in liquid of density

d_2

m_2

. The density of th object is