JEE MATHEMATICS MCQ: RELATIONS

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Application +4 | -1

If two sets

A

and

B

are having 99 elements in common, then the number of elements common to each of the sets

A \times B

and

B \times A

are

View answer and explanation

Correct option: B

99^2

Option B (

99^2

) is correct because the number of common elements in

A \times B

and

B \times A

is the square of the number of common elements in A and B.

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\mathrm{Z}

R

\mathrm{N}

\mathrm{R}

\mathrm{N} \times \mathrm{N}

(\mathrm{a}, \mathrm{b}) \mathrm{R}(\mathrm{c}, \mathrm{d})

a d(b+c)=b c(a+d)

\mathrm{R}

W

R

R=\{(x, y) \in W \times W \mid

x

y

\}

S

R = \{ \left( {a,\;b} \right):1 + ab > 0\}

S

X

R

X

A

B

R

R

N

R = \left\{ {\left( {x,\;y} \right):4x + 3y = 20} \right\}

R