JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

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Application +4 | -1

\int \sin 2 x \log _e \cos x d x

is equal to

View answer and explanation

Correct option: C

\left(\frac{1}{2}-\log _e \cos x\right) \cos ^2 x+C

Option C,

\left(\frac{1}{2}-\log _e \cos x\right) \cos ^2 x+C

, is correct because it results from integrating

\sin 2x \log_e \cos x

using integration by parts and substitution.

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