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JEE PHYSICS MCQ: OSCILLATIONS

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The time period of a simple pendulum measured inside a stationary elevator is 4 s4 {~s}. If the lift start accelerating downwards with an acceleration 3g/43 g / 4, the time period will be
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Correct option: B
8 s8 {~s}
Option B (8 s) is correct because the effective acceleration changes when the elevator accelerates downwards, affecting the time period of the pendulum.

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