JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

x+i y=\frac{1}{1-\cos \theta+2 i \sin \theta}, \theta \neq 2 n \pi, n \in \boldsymbol{I}

, then maximum value of

x

View answer and explanation

Correct option: C

\frac{1}{2}

Option C (

\frac{{1}}{{2}}

) is correct because the maximum value of x occurs when

\cos \theta = -1

, resulting in

x = \frac{{1}}{{2}}

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\left|\sum\limits_{r=1}^n z_r\right|

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\alpha, \beta

\gamma

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