Skip to main content
Back to FUNCTIONS

JEE MATHEMATICS MCQ: FUNCTIONS

1 Medium
1 of 1
Application +4 | -1
f(x)=sin⁡−1(log⁡2x)f\left( x \right) = \sqrt {{{\sin }^{ - 1}}\left( {{{\log }_2}x} \right)} exists for
View answer and explanation
Correct option: B
x∈[1,  2]x \in \left[ {1,\;2} \right]
Option B (x∈[1,  2]x \in \left[ {1,\;2} \right]) is correct because the function exists when the argument of the square root is non-negative and the argument of the inverse sine lies between -1 and 1.

More Questions from FUNCTIONS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.