JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Hard

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Application +4 | -1

Tangent is drawn to ellipse

\frac{{{x^2}}}{{27}} + {y^2} = 1\,at\,\left( {3\sqrt 3 \cos \theta ,\sin \theta } \right)\,(where\,\theta \in \left( {0,\;\pi /2} \right))

. Then the value of

\theta

such that sum of intercepts on axes made by this tangent is minimum, is

View answer and explanation

Correct option: B

\frac{\pi }{6}

Option B

\frac{\pi }{6}

is correct because it minimizes the sum of the intercepts on the axes, found by setting the derivative of the sum equal to zero.

More Questions from TANGENTS & NORMALS

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z