JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Analyzing +4 | -1

The domain of the function

f\left( x \right) = \frac{{{{\sin }^{ - 1}}\left( {x - 3} \right)}}{{\sqrt {9 - {x^2}} }},

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Correct option: B

\left[ {2,\;3} \right)

Option B is correct because it satisfies both conditions: -1 <= x-3 <= 1 and 9 - x² > 0, considering the denominator cannot be zero.

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