JEE MATHEMATICS MCQ: FUNCTIONS

1 Medium

1 of 1

Application +4 | -1

Given

f(x)=\frac{1}{(1-x)}, g(x)=f\{f(x)\}

and

h(x)=f[f\{f(x)\}]

. Then the value of

f(x) \cdot g(x) \cdot h(x)

View answer and explanation

Correct option: B

-1

Option B (-1) is correct because after evaluating the functions f(x), g(x), and h(x), their product simplifies to -1.

More Questions from FUNCTIONS

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}