Skip to main content
Back to CHEMICAL BONDING & MOLECULAR STRUCTURE

JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

1 Easy
1 of 1
Remembering +4 | -1
The carbon atoms of graphite are
View answer and explanation
Correct option: A
sp2sp^2 hybridised
Option A (sp2sp^2 hybridised) is correct because each carbon atom in graphite is bonded to three other carbon atoms in a planar arrangement, resulting in sp2sp^2 hybridization.

More Questions from CHEMICAL BONDING & MOLECULAR STRUCTURE

Practice All Chapter MCQs →
The hybridization in sulphur dioxide is CO2\mathrm{C}{\mathrm{O}_2} has the same geometry as: (A)HgCl2,(B)NO2,(C)SnCl4,(D)C2H2\left( A \right)\mathrm{HgC}{\mathrm{l}_2},\left( B \right)\mathrm{N}{\mathrm{O}_2},\left( C \right)\mathrm{SnC}{\mathrm{l}_4},\left( D \right){\mathrm{C}_2}{\mathrm{H}_2} The pair of molecules forming strongest hydrogen bonds are Paramagnetism is shown by Which statement is correct? Assertion (A) : BF3{BF}_3 is a weaker Lewis acid than BCl3{BCl}_3.

Reason (R) : The planar BF3{BF}_3 molecule is stabilised to a greater extent than BCl3{BCl}_3 by B−Xπ{B}-X \pi-bonding.
Type at least 2 characters or jump directly:
🩺 NEET MCQs 🔬 JEE MCQs 🎯 JEE College Predictor Study guides 📊 Dashboard
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.

Continue with Free Account →