JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

1 Easy

1 of 1

Remembering +4 | -1

The bond angle in carbon tetrachloride is approximately

View answer and explanation

Correct option: B

109^{\circ}

Option B (

109^{\circ}

) is correct because carbon tetrachloride (

CCl_4

) has a tetrahedral geometry due to

sp^3

hybridization, resulting in a bond angle of approximately 109.5 degrees.

More Questions from CHEMICAL BONDING & MOLECULAR STRUCTURE

Practice All Chapter MCQs →

\mathrm{C}{\mathrm{O}_2}

\left( A \right)\mathrm{HgC}{\mathrm{l}_2},\left( B \right)\mathrm{N}{\mathrm{O}_2},\left( C \right)\mathrm{SnC}{\mathrm{l}_4},\left( D \right){\mathrm{C}_2}{\mathrm{H}_2}

{BF}_3

{BCl}_3

{BF}_3

{BCl}_3

{B}-X \pi