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JEE PHYSICS MCQ: DUAL NATURE OF RADIATION AND MATTER

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An electron with mass 'm' with an initial velocity (t=0)(\text{t}=0) v⃗=v0i^(v0>0)\vec{\mathrm{v}}=\mathrm{v}_0 \hat{\mathrm{i}} \left(\mathrm{v}_0>0\right) enters a magnetic field B⃗=B0j^.\vec{\mathrm{B}}=\mathrm{B}_0 \hat{\mathrm{j}}. If the initial de-Broglie wavelength at t=0\mathrm{t}=0 is λ0\lambda_0 then its value after time 't' would be:
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Correct option: D
λ0\lambda_0
Option D (λ0\lambda_0) is correct because the magnetic force does no work on the electron, so its speed remains constant, and therefore its de Broglie wavelength remains constant.

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