JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

If the function

f:N \to N

is defined by

f\left( x \right) = \sqrt x

, then

\frac{{f\left( {25} \right)}}{{f\left( {16} \right) + f\left( 1 \right)}}

is equal to

View answer and explanation

Correct option: D

1

The correct answer is D (1) because substituting the values into the function and simplifying results in 1.

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f\left( x \right) = x - \left[ x \right]

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f(x)=x^4

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S=\left\{x: f(x)=f^{-1}(x)\right\}