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JEE MATHEMATICS MCQ: STRAIGHT LINES

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Analyzing +4 | -1
A≡(−4,0),B≡(4,0),MA \equiv(-4,0), B \equiv(4,0), M and NN are variable points on YY-axis such that MM lies below NN and MN=4M N=4. If the line joining AMA M and BNB N intersect at PP, then locus of PP is
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Correct option: B
2xy−16+x2=02 x y-16+x^2=0
The correct answer is B (2xy−16+x2=02xy-16+x^2=0) because the locus of point P is found by eliminating the parameter 'h' from the equations of lines AM and BN.

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