When copper is heated with conc. ${\rm{HN}}{{\rm{O}}_3}$ it produces:

${\rm{Cu(N}}{{\rm{O}}_3}{{\rm{)}}_2}\,\,{\rm{and}}\,{\rm{N}}{{\rm{O}}_2}$

${\rm{Cu(N}}{{\rm{O}}_3}{{\rm{)}}_2}\,\,{\rm{and}}\,{\rm{NO}}$

${\rm{Cu(N}}{{\rm{O}}_3}{{\rm{)}}_2},\,{\rm{NO}}\,\,{\rm{and}}\,{\rm{N}}{{\rm{O}}_2}$

${\rm{Cu(N}}{{\rm{O}}_3}{{\rm{)}}_2}\,{\rm{and}}\,{{\rm{N}}_2}{\rm{O}}$

JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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Understanding +4 | -1

When copper is heated with conc.

\mathrm{HN}{\mathrm{O}_3}

it produces:

View answer and explanation

Correct option: A

\mathrm{Cu(N}{\mathrm{O}_3}{\mathrm{)}_2}\,\,\mathrm{and}\,\mathrm{N}{\mathrm{O}_2}

Option A is correct because copper reacts with concentrated nitric acid to produce copper nitrate and nitrogen dioxide.

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17^{\text {th }}

{O}_2

{O}_2

\mathrm{C}{\mathrm{N}^ - }

{\mathrm{N}_2}

\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2}

2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+}

{H}_2 {~S}_2 {O}_8

{S}={O}

{S}-{OH}

{O}-

{O}

{NH}_3

{H}_2 {SO}_4

{H}_2 {SO}_4