JEE PHYSICS MCQ: THERMODYNAMICS

1 Medium

1 of 1

Remembering +4 | -1

In gases of diatomic molecules, the ratio of the two specific heats of gases

{C_P}/{C_V}

View answer and explanation

Correct option: B

1.40

Option B (

1.40

) is correct because for diatomic gases, the ratio of specific heats,

{C_P}/{C_V}

, is approximately 1.40.

More Questions from THERMODYNAMICS

Practice All Chapter MCQs →

0.25\,\,{m^3}

{10^3}N/{m^2},

T

P

V

\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)