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JEE PHYSICS MCQ: THERMODYNAMICS

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Analyzing +4 | -1
Assertion: Between states (P1,V1,T1)\left(\mathrm{P}_1, \mathrm{V}_1, \mathrm{T}_1\right) and (P2,V2,T2)\left(\mathrm{P}_2, \mathrm{V}_2, \mathrm{T}_2\right), work done in two step process is more than work done in one step process.
Reason: Work done is a path function.
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Correct option: D
If both Assertion & Reason are false
Option D (If both Assertion & Reason are false) is correct because work done depends on the process, and work done is a path function.

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The work done in which of the following process is zero? Water is used to cool the radiators of engines in cars because A gas expand 0.25  m30.25\,\,{m^3} at constant pressure 103N/m2,{10^3}N/{m^2}, the work done is A thermodynamic process in which temperature TT of the system remains constant though other variable PP and VV may change, is called What is the slope for an isothermal process? For adiabatic processes (γ=CpCv)\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)
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