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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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The smallest positive number pp for which the equation cos⁡(psin⁡x)=sin⁡(pcos⁡x)\cos (p \sin x)=\sin (p \cos x) has a solution x∈[0,2π]x \in[0,2 \pi], is equal to
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Correct option: D
π22\frac{\pi}{2 \sqrt{2}}
Option D (π22\frac{\pi}{2 \sqrt{2}}) is correct because it is the smallest positive value of pp that satisfies the given equation.

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