JEE MATHEMATICS MCQ: ELLIPSE

1 Hard

1 of 1

Application +4 | -1

If the focal distance of an end of the minor axis of an ellipse (referred to its axes as the axes of

x

and

y

respectively) is

k

and the distance between its foci is

2h

, then its equation is

View answer and explanation

Correct option: B

\frac{{{x^2}}}{{{k^2}}} + \frac{{{y^2}}}{{{k^2} - {h^2}}} = 1

Option B (

\frac{{{x^2}}}{{{k^2}}} + \frac{{{y^2}}}{{{k^2} - {h^2}}} = 1

) is correct because it correctly relates the focal distance and the distance between the foci to the equation of the ellipse.

More Questions from ELLIPSE

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\frac{x^2}{144}+\frac{y^2}{81}=1

m

\mathrm{M}

\mathrm{mM}

P

\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1

S

S'.

A

PSS',

A

A

B

(\sqrt{7}, 0)

(-\sqrt{7}, 0)

P

9 x^{2}+16 y^{2}=144

\mathrm{PA}+\mathrm{PB}

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

r

\frac{x^2}{25}+\frac{y^2}{16}=1

P

x=0

Q

R

Q

y=x

Q

R

N P

Q

P

O