JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1

\alpha

and

\beta

are the eccentric angles of the extremities of a focal chord of an ellipse, then the eccentricity of the ellipse, is

View answer and explanation

Correct option: D

\frac{\sin \alpha+\sin \beta}{\sin (\alpha+\beta)}

Option D (

\frac{{\sin \alpha + \sin \beta}}{{\sin (\alpha + \beta)}}

) is correct because the eccentricity is derived using the equation of a focal chord and the properties of eccentric angles.

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