Skip to main content
Back to MECHANICAL PROPERTIES OF FLUIDS

JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

1 Medium
1 of 1
Application +4 | -1
The surface tension of soap solution is 0.03Nm−10.03\mathrm{N}{\mathrm{m}^{ - 1}}. the work done in blowing to from a soap bubble of surface area 40cm2,(inJ),is40\mathrm{c}{\mathrm{m}^2},\left( {\mathrm{in J}} \right),\mathrm{is}
View answer and explanation
Correct option: B
2.4×10−42.4 \times {10^{ - 4}}
Option B (2.4×10−42.4 \times {10^{ - 4}}) is correct because the work done in forming a soap bubble is calculated using the formula W=T×2×ΔAW = T \times 2 \times \Delta A.

More Questions from MECHANICAL PROPERTIES OF FLUIDS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.