JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

The period of the function

f(x)=2 \cos \frac{1}{3}(x-\pi)

is:

View answer and explanation

Correct option: A

6 \pi

The correct answer is A (6π) because the period of cos(kx) is 2π/k, and in this case, k = 1/3.

More Questions from FUNCTIONS

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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f^{-1}(x)

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f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}