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JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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Analyzing +4 | -1
MF+XeF4→A′(M+={MF}+{XeF}_4 \rightarrow {A}^{\prime}\left({M}^{+}=\right.Alkalimetalcation ))
The state of hybridisation of the central atom in 'AA' and shape of the species are:
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Correct option: C
sp3 d3{sp}^3 {~d}^3, pentagonal planar
The correct answer is sp3 d3{sp}^3 {~d}^3, pentagonal planar because MF{MF} reacts with XeF4{XeF}_4 to form M+[XeF5−]{M}^{+}[{XeF}_5^{-}], which has a pentagonal planar structure and sp3 d3{sp}^3 {~d}^3 hybridization.

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