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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1
If z=−12+i32z=\frac{-1}{2}+i \frac{\sqrt{3}}{2}, then 8+10z+7z28+10 z+7 z^2 is equal to
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Correct option: C
−12+i332\frac{-1}{2}+i \frac{3 \sqrt{3}}{2}
Option A ((0,2 tan-1 1/4]) is correct because it is the interval for 'a' where the discriminant of the quadratic equation is greater than zero.

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