NEET UG CHEMISTRY MCQ: ELECTRO CHEMISTRY

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Deduce from the following

{E^ \circ }

values of half cells, what combination of two half cells would result in a cell with the largest potential?

i)

{A^{3 - }} \to {A^{2 - }} + e;

{E^ \circ } = 1.5\mathrm{V}

ii)

{B^{2 + }} + e \to {B^ + }

;

{E^ \circ } = - 2.1\mathrm{V}

iii)

{C^{2 + }} + e \to {C^ + }

;

{E^ \circ } = 0.5\mathrm{V}

iv)

D \to {D^{2 + }} + 2e

;

{E^ \circ } = - 1.5\mathrm{V}

View answer and explanation

Correct option: C

(ii) and (iv)

Option A (i) and (ii) is correct because the largest potential difference is achieved when the reduction potential is most positive and the oxidation potential is most negative.

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