JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Analyzing +4 | -1

The imaginary part of

\left( {z - 1} \right)(\cos \alpha - i\sin \alpha ) + {\left( {z - 1} \right)^{ - 1}} \times (\cos \alpha + i\sin \alpha )

zero, if

View answer and explanation

Correct option: C

\arg \left( {z - 1} \right) = \mathrm{\alpha }

Option C (

\arg \left( {z - 1} \right) = \mathrm{\alpha }

) is correct because the imaginary part of the expression is zero when

\arg(z-1) = \alpha

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