JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

f\left( {\sin x} \right) - f\left( { - \sin x} \right) = {x^2} - 1

is defined for all

x \in R,

then the value of

{x^2} - 2

can be

View answer and explanation

Correct option: D

-1

Option D (-1) is correct because by substituting -x for x and adding the equations, we find that x² = 1, and thus x² - 2 = -1.

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