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JEE MATHEMATICS MCQ: FUNCTIONS

1 Hard
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Application +4 | -1
Let g(x)=ex−e−x2g(x)=\frac{e^x-e^{-x}}{2} and g(f(x))=xg(f(x))=x, then f(e22−12e11)−5=f\left(\frac{e^{22}-1}{2 e^{11}}\right)-5=
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Correct option: A
6
Option A (6) is correct because finding the inverse of g(x) and substituting the given value results in f(x) = 11, thus f(x) - 5 = 6.

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