JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1

\int \frac{x+\left(\cos ^{-1} 3 x\right)^2}{\sqrt{1-9 x^2}} d x=A \sqrt{1-9 x^2}+B\left(\cos ^{-1} 3 x\right)^3+c

, where

{c}

is integration constant, then the values of

{A}

and

{B}

are:

View answer and explanation

Correct option: A

{A}=-\frac{1}{9}, {~B}=-\frac{1}{9}

Option A (

{A}=-\frac{1}{9}, {~B}=-\frac{1}{9}

) is correct because it represents the correct values of A and B after integration and comparison.

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