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JEE PHYSICS MCQ: RAY OPTICS

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The radii of curvature of a double convex lens of glass (μ=1.5)(\mu=1.5) are in the ratio 1:21: 2. This lens renders the rays parallel coming from an illuminated filament at a distance of 6 cm6 \mathrm{~cm}. Calculate the radii of curvature of its surfaces.
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Correct option: D
−9.0 cm-9.0 \mathrm{~cm}
Option D (−9.0 cm-9.0 \mathrm{~cm}) is correct because it is the calculated radius of curvature of the second surface of the lens using the lens maker's formula.

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