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JEE PHYSICS MCQ: RAY OPTICS

1 Medium
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Application +4 | -1
Find the angle of refraction in a medium (μ=2)(\mu=2) if light is incident in vacuum, making angle equal to twice the critical angle.
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Correct option: A
sin⁡−1(34)\sin ^{-1}\left(\frac{\sqrt{3}}{4}\right)
Option A (sin⁡−1(34)\sin ^{-1}(\frac{\sqrt{3}}{4})) is correct because it's calculated using Snell's Law and the relationship between critical angle and refractive index.

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