$\mathop \smallint \nolimits_0^2 \,\,\frac{{2x\,\, - \,\,2}}{{2x\,\, - \,\,{x^2}}}\,\,dx$ is equal to

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

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Analyzing +4 | -1

\int \nolimits_0^2 \,\,\frac{{2x\,\, - \,\,2}}{{2x\,\, - \,\,{x^2}}}\,\,dx

is equal to

View answer and explanation

Correct option: A

Option A (0) is correct because substituting

t = 2x - x^2

makes the limits of integration the same, resulting in a zero integral.

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