A solution of ${\rm{KMn}}{{\rm{O}}_4}$ is reduced to ${\rm{Mn}}{{\rm{O}}_2}.$ The normality of solution is 0.6. The molarity is:

NEET UG CHEMISTRY MCQ: REDOX REACTIONS

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A solution of

\mathrm{KMn}{\mathrm{O}_4}

is reduced to

\mathrm{Mn}{\mathrm{O}_2}.

The normality of solution is 0.6. The molarity is:

View answer and explanation

Correct option: D

0.2M

Option D (0.2M) is correct because the normality is related to molarity by the n-factor, which is 3 in this case, so Molarity = Normality / n-factor.

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{I_2}

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }