If $ f(x)=\log \frac{1+x}{1-x} $, then $ f(x) $ is

$ f\left(x_{1}\right) f\left(x_{2}\right)=f\left(x_{1}+x_{2}\right) $

$ \frac{f\left(x_{1}\right)}{f\left(x_{2}\right)}=f\left(x_{1}-x_{2}\right) $

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Understanding +4 | -1

f(x)=\log \frac{1+x}{1-x}

, then

f(x)

View answer and explanation

Correct option: D

Odd function

Option D (Odd function) is correct because

f(-x) = -f(x)

, which is the definition of an odd function.

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